Content-Length: 676 | pFad | http://github.com/javascript-tutorial/en.javascript.info/pull/3946.diff
thub.com diff --git a/9-regular-expressions/07-regexp-escaping/article.md b/9-regular-expressions/07-regexp-escaping/article.md index 1ad3ac98c9..7af0dec461 100644 --- a/9-regular-expressions/07-regexp-escaping/article.md +++ b/9-regular-expressions/07-regexp-escaping/article.md @@ -65,7 +65,7 @@ The similar search in one of previous examples worked with `pattern:/\d\.\d/`, b The reason is that backslashes are "consumed" by a string. As we may recall, regular strings have their own special characters, such as `\n`, and a backslash is used for escaping. -Here's how "\d\.\d" is perceived: +Here's how "\d\\.\d" is perceived: ```js run alert("\d\.\d"); // d.dFetched URL: http://github.com/javascript-tutorial/en.javascript.info/pull/3946.diff
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